Sound - Questions and Answers

Chapter Questions

Section 11.2

1. How does the sound produced by a vibrating object in a medium reach your ear?

The vibrating object creates compressions and rarefactions in the medium. These pressure variations travel through the medium as a wave. When this wave reaches our ear, it causes our eardrum to vibrate, which our brain interprets as sound.

2. Explain how sound is produced by your school bell.

When the school bell is struck, it vibrates. These vibrations create compressions and rarefactions in the surrounding air, which propagate as sound waves that travel to our ears.

3. Why are sound waves called mechanical waves?

Sound waves are called mechanical waves because they require a material medium (solid, liquid, or gas) for propagation. They involve the physical movement of particles in the medium.

4. Suppose you and your friend are on the moon. Will you be able to hear any sound produced by your friend?

No, because sound requires a medium to travel, and the moon has no atmosphere (it's a vacuum). Without a medium, sound waves cannot propagate.

Section 11.2.2

1. Which wave property determines (a) loudness, (b) pitch?

(a) Amplitude determines loudness
(b) Frequency determines pitch

2. Guess which sound has a higher pitch: guitar or car horn?

A guitar typically has a higher pitch than a car horn. Guitar strings vibrate at higher frequencies, producing higher-pitched sounds.

1. What are wavelength, frequency, time period and amplitude of a sound wave?

- Wavelength: Distance between two consecutive compressions or rarefactions
- Frequency: Number of oscillations per unit time
- Time period: Time taken for one complete oscillation
- Amplitude: Maximum displacement of particles from their mean position

2. How are the wavelength and frequency of a sound wave related to its speed?

Speed of sound (v) = Wavelength (λ) × Frequency (ν)
v = λν

3. Calculate the wavelength of a sound wave whose frequency is 220 Hz and speed is 440 m/s in a given medium.

Using the formula: v = λν
λ = v/ν = 440/220 = 2 m
The wavelength is 2 meters.

4. A person is listening to a tone of 500 Hz sitting at a distance of 450 m from the source of the sound. What is the time interval between successive compressions from the source?

The time interval between successive compressions is the time period (T) of the wave.
T = 1/ν = 1/500 = 0.002 s or 2 ms

1. Distinguish between loudness and intensity of sound.

Intensity is the amount of sound energy passing each second through unit area. It is an objective physical quantity. Loudness is a subjective measure of how our ears perceive the intensity of sound. Two sounds of equal intensity may be perceived as having different loudness by our ears.

Section 11.2.3

1. In which of the three media, air, water or iron, does sound travel the fastest at a particular temperature?

Sound travels fastest in iron, then water, and slowest in air. At 25°C, the speeds are approximately: iron - 5950 m/s, water - 1498 m/s, air - 346 m/s.

Section 11.3

1. Why are the ceilings of concert halls curved?

Ceilings of concert halls are curved to ensure that sound, after reflection, reaches all corners of the hall evenly. This helps in distributing sound uniformly throughout the audience area.

Section 11.4

1. What is the audible range of the average human ear?

The audible range for the average human ear is from about 20 Hz to 20,000 Hz (20 kHz).

2. What is the range of frequencies associated with (a) Infrasound? (b) Ultrasound?

(a) Infrasound: Frequencies below 20 Hz
(b) Ultrasound: Frequencies above 20,000 Hz (20 kHz)

Exercises

1. What is sound and how is it produced?

Sound is a form of energy that produces a sensation of hearing in our ears. It is produced by vibrating objects. When an object vibrates, it sets the particles of the surrounding medium into vibration, creating compressions and rarefactions that propagate as sound waves.

2. Describe with the help of a diagram, how compressions and rarefactions are produced in air near a source of sound.

When a vibrating object moves forward, it pushes and compresses the air in front of it, creating a region of high pressure called compression. When it moves backward, it creates a region of low pressure called rarefaction. As the object continues to vibrate, a series of compressions and rarefactions is created in the air, forming a sound wave that propagates through the medium.

3. Why is sound wave called a longitudinal wave?

Sound waves are called longitudinal waves because the particles of the medium vibrate parallel to the direction of wave propagation. The particles move back and forth in the same direction that the wave is traveling, creating regions of compression and rarefaction.

4. Which characteristic of the sound helps you to identify your friend by his voice while sitting with others in a dark room?

The quality or timbre of sound helps identify your friend's voice. Quality is that characteristic of sound which enables us to distinguish between different sounds having the same pitch and loudness.

5. Flash and thunder are produced simultaneously. But thunder is heard a few seconds after the flash is seen, why?

This happens because light travels much faster than sound. Light travels at about 3×10^8 m/s, while sound travels at only about 340 m/s in air. Therefore, we see the flash almost instantly, but the sound takes time to reach us.

6. A person has a hearing range from 20 Hz to 20 kHz. What are the typical wavelengths of sound waves in air corresponding to these two frequencies? Take the speed of sound in air as 344 m/s.

Using the formula: λ = v/ν
For 20 Hz: λ = 344/20 = 17.2 m
For 20,000 Hz: λ = 344/20000 = 0.0172 m or 1.72 cm
The wavelengths range from 17.2 m to 1.72 cm.

7. Two children are at opposite ends of an aluminium rod. One strikes the end of the rod with a stone. Find the ratio of times taken by the sound wave in air and in aluminium to reach the second child.

Speed of sound in aluminium = 6420 m/s (from table)
Speed of sound in air = 346 m/s (from table)
Time = Distance/Speed
Since distance is same for both:
Ratio = Time in air / Time in aluminium = (d/346) / (d/6420) = 6420/346 ≈ 18.55
Sound takes about 18.55 times longer to travel through air than through aluminium.

8. The frequency of a source of sound is 100 Hz. How many times does it vibrate in a minute?

Frequency = 100 Hz means 100 vibrations per second
Vibrations in a minute = 100 × 60 = 6000 vibrations

9. Does sound follow the same laws of reflection as light does? Explain.

Yes, sound follows the same laws of reflection as light:
1. The angle of incidence is equal to the angle of reflection.
2. The incident sound wave, the reflected sound wave, and the normal to the reflecting surface at the point of incidence all lie in the same plane.

10. When a sound is reflected from a distant object, an echo is produced. Let the distance between the reflecting surface and the source of sound production remains the same. Do you hear echo sound on a hotter day?

Yes, but the minimum distance required to hear a distinct echo may be different. On a hotter day, the speed of sound increases (as speed of sound increases with temperature), so the time taken for sound to travel to the obstacle and back decreases. This might affect whether we hear a distinct echo or not, depending on the actual distance.

11. Give two practical applications of reflection of sound waves.

1. Stethoscope: Used by doctors to listen to sounds produced within the body. It works on multiple reflections of sound.
2. Megaphones or loudhailers: Designed to send sound in a particular direction without spreading it in all directions, using reflection.

12. A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 m/s² and speed of sound = 340 m/s.

Time for stone to fall: s = ½gt² → 500 = ½ × 10 × t² → t² = 100 → t = 10 s
Time for sound to travel up: t = distance/speed = 500/340 ≈ 1.47 s
Total time = 10 + 1.47 = 11.47 s
The splash is heard after approximately 11.47 seconds.

13. A sound wave travels at a speed of 339 m/s. If its wavelength is 1.5 cm, what is the frequency of the wave? Will it be audible?

Wavelength = 1.5 cm = 0.015 m
Frequency = Speed/Wavelength = 339/0.015 = 22,600 Hz = 22.6 kHz
This frequency is above the audible range for humans (20 Hz - 20 kHz), so it will not be audible to most people.

14. What is reverberation? How can it be reduced?

Reverberation is the persistence of sound in a hall due to repeated reflections from walls, ceiling, and other surfaces. It can be reduced by using sound-absorbent materials on the walls and ceiling, such as compressed fibreboard, rough plaster, draperies, and carpets.

15. What is loudness of sound? What factors does it depend on?

Loudness is the subjective measure of the intensity of sound as perceived by the human ear. It depends on:
1. The amplitude of the sound wave - greater amplitude means louder sound
2. The sensitivity of the human ear - our ears are more sensitive to some frequencies than others
3. The distance from the source - loudness decreases with distance

16. How is ultrasound used for cleaning?

Ultrasound is used for cleaning by placing objects in a cleaning solution and sending ultrasonic waves into the solution. The high frequency waves create microscopic bubbles that implode, generating strong cleaning action that dislodges dirt, grease, and contaminants from hard-to-reach places.

17. Explain how defects in a metal block can be detected using ultrasound.

Ultrasound waves are passed through the metal block. If there is a defect like a crack or hole, the ultrasound waves get reflected from the defective location. Detectors are used to identify these reflected waves. The pattern of reflected waves helps locate and identify the size and nature of the defect inside the metal block.